The area of rectangle varies jointly as the length l and the width w and a=180cm when l=9cm and w=5cm. find the area of a rectangle whose length is 20 cm and whose width is 5 cm.​

1) 6x2 = 12

12/2 = 6

heightxbase / 2

2) 5x3 = 15

length x width

3)  need to find the length of one of the sides (as each side is the same length) and then multiply this by itself to find the area

2. a. 49cm²

3. d. 63cm²

7. c or d. 81cm²

That's all I can do, I don't quite understand other question.

A. Perimeters

1. A square with side of 4cm

P = 4s

P = 16 cm

2. A parallelogram with a length of 7cm and a width of 8cm

P = 2(l + w)

P = 2(7 + 8)

P = 30 cm

B. Area of Squares

1. side = 5 cm

A = s²

A = (5)²

A = 25 cm²

2. side = 12 mm

A = s²

A = (12)²

A = 144 mm²

C. Area of Rectangles

1. length = 9 cm, width = 7 cm

A = lw

A = (9)(7)

A = 63 cm²

2. length = 8 cm, width = 5 cm

A = lw

A = (8)(5)

A = 40 cm²

D. Area of Parallelograms

1. b = 12cm, a = 6cm

A = ab

A = (6)(12)

A = 72 cm²

2. b = 6cm, a = 11cm

A = ab

A = (11)(6)

A = 66 cm²

E. Area of Triangles

1. b = 8m, a = 4m

A = (ab)/2

A = (4·8)/2

A = 16 m²

2. b = 14m, a = 6m

A = (ab)/2

A = (6·14)/2

A = 42 m²

A

D

C

A

B

Step-by-step explanation:

basta, tama 'yan magtiwala ka lang.

where is the figure below the number 1

Step-by-step explanation:

thanks

hope you understand

Width: X = 5cm

Length: x+5 = 10cm

Perimeter = 30cm

Step-by-step explanation:

10 is more than 5. Also 10 x 5 is 50

Perimeter

P = 2(l + w)

P = 2(10 + 5)

P = 2(15)

P = 30