Math, 28.10.2019 15:28 kuanjunjunkuan

How to solve direct square variation

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Answer from: ian2145

For direct square variation, use the equation/formula y = kx, where k is the constant of proportionality. For inverse variation, use the equation y = k/x, again, with k as the constant of proportionality. Remember that these problems might use the word 'proportion' instead of 'variation,' but it means the same thing.

Answer from: HaHannah

A = π r2. In the language of variation: the area A varies directly with the square of the radius r. ...and the constant of variation is k = π. This formula is an example of "direct" variation."Direct variation" means that, in the one term of the formula, the variable is "on top".

Answer from: nelspas422

Direct square variation problems are solved using the equation y = kx. In this case, you should use c and d instead of x and y and notice how the word “square root” changes the equation. Step 2: Use the information given in the problem to find the value of k. In this case, you need to find k when c = 6 and d = 256.

Answer from: stacy05

Direct variation :
Question :
y varies directly to x
y=kx
k is the constant
Inverse variation
Given: y=9
x=3
Formula; k=y÷x
Sol: k= 9÷3
k=3

Joint variation
F varies jointly as x and y
F=kxy

Answer from: 09389706948

In the language of variation: the area A varies directly with the square of the radius r. ...and the constant of variation is k = π. This formula is an example of "direct" variation. "Direct variation" means that, in the one term of the formula, the variable is "on top”.

Answer from: JUMAIRAHtheOTAKU

answer is on the pic.
If x varies directly as the square of y, and x=36 when y=12, find the constant of variation and the

Answer from: reyquicoy4321

answer:

HYPERBOL. PO YAN

#CARRYONLEARNING

Answer from: hannahleigh

area of a square
A = $s^{2}$
when s = 4cm, A = 16 $cm^{2}$
when s = 8cm, A = 64 $cm^{2}$
* When s was increased by 2cm, the increase in area was $2^{2}$ or 4 times

area of a circle
A = π $r^{2}$
when r = 4cm, A = 50.27 $cm^{2}$
when r = 8cm, A = 201.06 $cm^{2}$
* When s was increased by 2cm, the increase in area was $2^{2}$ or 4 times

Answer from: janalynmae

Direct variation is simply a varies directly to x (a=kx). while direct squared variation is a varies directly to the square of it (a= kx^2).

Answer from: ShairaGailSanchez

Direct variation problems are solved using the equation y = kx.; Find the value of k, this is usually a constant variation or proportionality; Redo the equation substituting the value of k; Follow through on the equation and add the remaining information, if this is a word problem remember to include units in the final answer