Calculate the number of moles of solute present in the
es of solute present in the following solutions:
a. 1.25 l of 4.28 m hcl
b. 85.3 g of aqueous solution that is 2.47 percent sucrose​

answer:

a. 195.06 g

b. 2.11

elaborate your question on letter b, i've got the answer on that one by using the formula of percent weight by weight (%w/w)

%w/w = weight solute/weight volume

a. 5.35 moles of solute

b.0.00616 mol sucrose

Explanation:

a.)

step 1: list all given variables

Volume = 1.25 L

Molarity = 4.28 M

Step 2: calculate the unknown

Molarity= mole of solute/Liter of solution

Mole of solute = molarity x liter of solution

            = 4.28 M x 1.25 L

            = 5.35 moles of solute

b.)

step 1: list all given variables

mass of solution = 85.3 g

mass % sucrose = 2.47 %

step 2: calculate the unknown

2.47%×1/100×85.3g×(1 mol sucrose)/(342.2965 grams sucrose)=0.00616 mol sucrose

answer:

Totok man

I hOPE iT wILL help

Explanation: